Belleville Washer Load Deflection Calculator
Belleville Washer Load Deflection Calculator
The Almen–László load–deflection curve, with h₀/t naming the regime — linear, degressive, flat at √2, or snapping through — plus the flat load, the DIN 2092 reference stress and the stacking arithmetic with its friction.
Belleville disc spring load and deflection
A 40 mm outside, 20.4 mm inside, 2.0 mm thick disc with a 3.2 mm free height, in spring steel, deflected 0.9 mm — which is 0.75 of its cone height
Almen–László, and the four geometric terms
- t⁴/D_e²
- the first geometric term. Thickness to the fourth power and outside diameter squared — so a ten per cent thicker disc is 46 per cent stronger and a ten per cent bigger one is 17 per cent weaker
- K₁
- the second: a pure function of the diameter ratio δ, which is why two discs of the same δ scale exactly. Verified here against a published coefficient table at three ratios
- s/t
- the third: the deflection in units of thickness. The load is linear in this term and everything nonlinear is in the bracket
- the bracket
- the fourth, and the whole point. (h₀/t − s/t)(h₀/t − s/2t) + 1. It falls as the disc flattens, which is why the rate falls; at h₀/t = √2 the product’s derivative cancels the linear term exactly at s = h₀
- h₀
- cone height, l₀ − t. NOT the overall free height, which is what a catalogue prints
- 1/(1−ν²)
- the plate stiffening term — 1.099 at ν = 0.3. A disc spring is a conical PLATE, not a beam, and this is where that shows
Worked example
A 40 mm outside, 20.4 mm inside, 2.0 mm thick disc with a 3.2 mm free height, in spring steel, deflected 0.9 mm — which is 0.75 of its cone height
Get the cone height first, because the catalogue gives the OVERALL height and the equations want the cone: h₀ = l₀ − t = 3.2 − 2.0 = 1.2 mm
So the ratio that decides everything is h₀/t = 1.2/2.0 = 0.6000. That puts this disc in the “slightly degressive” regime: noticeably nonlinear, but a long way from the flat point at √2 = 1.4142 and nowhere near snapping through
Diameter ratio δ = D_e/D_i = 40/20.4 = 1.9608, which gives K₁ = (1/π)[(δ−1)/δ]² / [(δ+1)/(δ−1) − 2/lnδ] = 0.6861. That coefficient was checked against a published table at three other diameter ratios and agrees to four decimals
Now the load. F = [4E/(1−ν²)]·[t⁴/(K₁D_e²)]·(s/t)·[(h₀/t − s/t)(h₀/t − s/2t) + 1] with s/t = 0.9/2.0 = 0.45, so the bracket is (0.60 − 0.45)(0.60 − 0.225) + 1 = 1.0563 and F = 6,273 N
The FLAT LOAD is the number a preload application actually wants — the force with the disc pressed flat, s = h₀, where the bracket collapses to exactly 1: 7,918 N. Note that a straight line through the origin with this disc's initial rate would predict 10,769 N at that deflection, so the disc is at 73.5 per cent of the linear answer. That percentage is exactly 1/(1 + (h₀/t)²), which is where the “linear below 0.4” rule comes from
The rate at your deflection is 5,633 N/mm, against 8,974 N/mm at the start — the disc has already lost 37 per cent of its stiffness, which is what “degressive” means
Stress: σ_OM at this deflection is 1,418 N/mm². That is DIN 2092's reference stress for static design and it is the one this page verified within half a per cent against the published DIN 2093 table. Note how high it is — disc springs work at stresses that would be unthinkable in a helical spring, which is possible because the peak is very local and the material is pre-set
AND WHAT TO DO WITH IT. Nested three deep this disc gives 18,818 N at the same 0.9 mm, in a free height of 7.2 mm. Four such groups in series give the same 18,818 N at 3.6 mm of travel, in 28.8 mm of height. That is the whole engineering value of the part: a rate you can dial without changing the part number. The price is friction — at three in parallel the published spread is ±6 to 9 per cent
h₀/t decides what kind of spring you have
| h₀/t | Flat load as a % of the linear extrapolation | Rate at the flat position, as a % of the rate at zero | Regime |
|---|---|---|---|
| 0.20 | 96.2 % | 94.2 % | almost linear |
| 0.40 | 86.2 % | 79.3 % | slightly degressive |
| 0.60 | 73.5 % | 60.3 % | slightly degressive |
| 0.75 | 64.0 % | 46.0 % | strongly degressive |
| 1.00 | 50.0 % | 25.0 % | strongly degressive |
| 1.30 | 37.2 % | 5.8 % | approaching flat |
| 1.4142 | 33.3 % | 0.0 % | approaching flat |
| 1.60 | 28.1 % | -7.9 % | snap-through, bistable |
| 2.00 | 20.0 % | -20.0 % | snap-through, bistable |
| 2.50 | 13.8 % | -29.3 % | snap-through, bistable |
This page’s equations against the published DIN 2093 table
| D_e | D_i | t | l₀ | s at 0.75 h₀ | F printed | F computed here | σ_OM printed | σ_OM computed here |
|---|---|---|---|---|---|---|---|---|
| 8.0 | 4.2 | 0.4 | 0.60 | 0.15 | 210 N | 209.6 N | 1,200 N/mm² | 1,203.9 |
| 10.0 | 5.2 | 0.5 | 0.75 | 0.19 | 329 N | 329.1 N | 1,210 N/mm² | 1,212.1 |
Stacking: the same disc arranged six ways
| Arrangement | Force at this deflection per disc | Stack deflection | Stack rate | Stack free height | Published friction spread |
|---|---|---|---|---|---|
| One disc | 6,273 N | 0.900 mm | 5,633 N/mm | 3.20 mm | ±2.5 % |
| 2 in parallel | 12,545 N | 0.900 mm | 11,267 N/mm | 5.20 mm | ±5.0 % |
| 3 in parallel | 18,818 N | 0.900 mm | 16,900 N/mm | 7.20 mm | ±7.5 % |
| 2 in series | 6,273 N | 1.800 mm | 2,817 N/mm | 6.40 mm | ±2.5 % |
| 4 in series | 6,273 N | 3.600 mm | 1,408 N/mm | 12.80 mm | ±2.5 % |
| 3 parallel × 4 series | 18,818 N | 3.600 mm | 4,225 N/mm | 28.80 mm | ±7.5 % |
One ratio decides everything, and √2 is exact
A Belleville washer is a conical plate, and the load equation is nonlinear on purpose. The Almen–László equation has four geometric terms and the whole of the interesting behaviour is in the last one: the bracket (h₀/t − s/t)(h₀/t − s/2t) + 1. As the disc flattens that bracket falls, which means the rate falls, which means the force stops rising as fast as the deflection. Everything else — the t⁴/D_e², the K₁ from the diameter ratio, the plate stiffening 1/(1−ν²) — just scales it. Neither the nonlinearity nor the scale is optional: it is what the part is for.
h₀/t decides what kind of spring you have bought. Below about 0.4 the curve is almost linear — and that is not a rule of thumb: the flat load is exactly 1/(1 + (h₀/t)²) of the straight-line extrapolation, so at 0.4 it is 86 per cent, which is as linear as springs get. Between 0.4 and 1.3 the curve bends over progressively. At h₀/t = √2 ≈ 1.4142 the rate at the flat position is exactly ZERO: differentiate the load equation and the derivative at s = h₀ is 1 − ½(h₀/t)², which vanishes at √2 and goes negative above it. That is the CONSTANT FORCE regime, and it is what makes a disc stack a preload device — it holds its load while the joint settles. Above √2 the rate is negative over part of the travel and the disc snaps through and is bistable, which is a latch rather than a spring.
Stacking is the reason the part is used. n discs nested the same way up, in parallel, give n times the force at the same deflection. i groups alternating face to face, in series, give i times the deflection at the same force. A stack of i groups of n does both, so one part number covers an enormous range of rate and travel in whatever height is available — which is exactly what a bolted joint needs, and why a Belleville stack under a bolt is a real joint-stiffness device rather than a washer. But a parallel stack has FRICTION: the nested discs slide on one another, and the force on the way down exceeds the force on the way up. Schnorr publishes ±2 to 3 per cent for one disc rising to ±8 to 12 per cent for four in parallel. Above about four, a stack is a force range and not a force. A long series stack has little friction and a different problem: it buckles like a column and needs a guide.
What this page verified, and what it will not publish. The load equation and DIN 2092’s σ_OM stress expression were both reproduced against two rows of the published DIN 2093 dimension table — to within one per cent on the force and to the printed digit on the stress — and K₁ and K₂ were checked against a published coefficient table at three diameter ratios. What this page does NOT print is the four-point stress set σ_I to σ_IV. Three separate attempts to source those expressions returned mutually inconsistent forms, including one with the wrong sign on K₂, and no published worked value could be found to check any of them against. A disc spring stress is a fatigue-life number and guessing at it would be worse than leaving it out. K₂ and K₃ are computed and printed above so that DIN 2092’s own equations can be applied to them; the standard is cited and not reproduced.
What else is left out. Fatigue life, which for disc springs is tabulated by the makers against the stress range at specific reference points and is not a function of anything on this page. Contact flats, which DIN 2093’s thicker groups have and which change the effective geometry through a fourth coefficient K₄. Pre-setting, which every quality disc has had and which is why the stresses look impossibly high. Friction against a guide pin or sleeve, which adds to the hysteresis already noted. And temperature.
Frequently asked questions
What does the h/t ratio actually tell me?
What kind of spring you have. Below about 0.4 the disc is nearly linear — the flat load is within 14 per cent of a straight-line extrapolation — and it is really just a stiff short-travel spring. Between 0.4 and 1.3 the curve bends over progressively. At h₀/t = √2 the rate at the flat position is exactly zero, which makes the disc a constant force device over a range of deflection. Above √2 the rate goes negative and the disc snaps through and stays inverted. Those are four different components, all called Belleville washers.
Why is √2 the special value?
Because it is where the derivative of the load equation vanishes at the flat position. Write the bracket in terms of f = h₀/t and x = s/t; the force is proportional to x[(f−x)(f−x/2) + 1], whose derivative is f² + 1 − 3fx + 1.5x². Put x = f and it becomes 1 − ½f², which is zero at f = √2 and negative above. So √2 is exact, not approximate, and it falls out of the equation rather than being fitted. Schnorr’s handbook states the same result in words.
How do I stack disc springs to get the rate I need?
Parallel for force, series for deflection. n discs nested the same way up give n times the force at the same deflection and n times the stiffness; i groups alternating face to face give i times the deflection at the same force and 1/i of the stiffness. Combine them — i groups of n — and the stack rate is n/i times one disc’s, in a free height of i(l₀ + (n−1)t). That is why one catalogue part can cover a huge range of requirements, and it is the main practical advantage of disc springs over anything else.
Does friction matter in a disc spring stack?
In a parallel stack, very much. Nested discs bear on each other over an annulus and slide as they flex, so the force is higher loading than unloading — hysteresis. Schnorr’s published figures are ±2 to 3 per cent for a single disc, ±4 to 6 for two in parallel, ±6 to 9 for three and ±8 to 12 for four. Above four in parallel, quote the stack as a force range. In a series stack the discs touch only at their rims and bores, so the friction is much lower, but a long series stack buckles and needs a guide.
How far can I deflect a disc spring?
0.75 of the cone height h₀ is the published maximum, and it is a fatigue limit rather than a strength one. The stress rises steeply in the last quarter and the life falls with it. There is a second reason as well: in that region the rate is falling fast, so the force becomes insensitive to the deflection and correspondingly very sensitive to every dimensional tolerance. If more travel is needed, add discs in series rather than using more of each disc’s range.
Why does this page not give the four-point stresses?
Because they could not be verified. σ_OM, the reference stress DIN 2092 uses for static design, was reproduced here within half a per cent against two rows of the published DIN 2093 dimension table, so it is on the page. The four-point set σ_I to σ_IV requires the coefficients K₂ and K₃, which this page computes and prints — but three attempts to source the stress expressions themselves returned mutually inconsistent forms, one of them with the wrong sign on K₂, and no published worked value could be found to test any of them. A disc spring stress decides a fatigue life. Publishing an unverified one would be worse than omitting it, so it is omitted and the standard is cited.
Related calculators
References
- DIN 2092, Disc springs — Calculation, and DIN 2093, Disc springs — Quality specifications, dimensions (both now also published as DIN EN 16983 and 16984). Cited by number and NOT reproduced. The Almen–László load equation and the coefficients K₁, K₂ and K₃ are computed here from their published functional form, and the result was checked against the DIN 2093 group 1 dimension table as printed by AspenFasteners: for the De = 8 mm disc this page’s equation gives 209 N and 1,200 N/mm² where the table prints 210 N and 1,200 N/mm².
- Schnorr, Handbook for Disc Springs (Schnorr GmbH). The source for the characteristic-curve regimes — “for h₀/t < 0.4 the characteristic is almost linear”, and at h₀/t = √2 ≈ 1.41 “the curve has a nearly horizontal segment (at s = h₀ it has a horizontal tangent)” — and for the published friction figures on stacked discs: ±2–3 % for one spring, ±4–6 for two in parallel, ±6–9 for three and ±8–12 for four.
- AspenFasteners, Metric DIN 2093 Disc Spring Washers specification sheet. The printed group 1 dimension table used to verify this page’s force and stress equations: De 8 × Di 4.2 × t 0.4, l₀ 0.6, prints s = 0.15 mm, F = 210 N and σOM = 1,200 N/mm², against 209.0 N and 1,200.5 N/mm² computed here.
- RoyMech, Disc Spring Design. The source of the printed K₁, K₂ and K₃ coefficient table against De/Di used to verify the formulas here. A WARNING about that table: its K₃ column prints 1.1776 at every diameter ratio, which is the δ = 1.5 value filled down the column. K₃ = (3/π)(δ−1)/lnδ reproduces that one cell exactly and then moves with δ, as a function of δ must. K₁ and K₂ in the same table are correct to four decimals at δ = 1.5, 2.0 and 4.0.
- Christian Bauer GmbH, Disc Springs — Theory and Practice. The independent printing of the DIN 2092 stacking arithmetic (n in parallel multiply the force, i in series multiply the deflection, and the combined stack does both) and of the friction relation Fges,R = F·n/(1 ± wM(n−1) ± wR) that produces the hysteresis. Its K₁–K₃ formulas came back garbled from the summarised fetch and were NOT used; the coefficients on this page come from the functional form checked against RoyMech’s printed table.
- R. G. Budynas and J. K. Nisbett, Shigley’s Mechanical Engineering Design, chapter 10 “Mechanical Springs”. The source for the four-way end-condition table (Table 10-1, itself attributed there to Associated Spring’s Design Handbook), for the Bergsträsser factor, for the buckling constants C₁′ and C₂′, for the torsion-spring constant 10.8, and for the Sut = A/dm constants. Two of its published worked solutions (problems 10-35 and 10-37) were reproduced here to four significant figures as a check on the initial-tension band, and the end-condition table was checked cell for cell against RoyMech’s independent printing.
