Watts to Amps Calculator (and Amps to Watts)
Watts to Amps Calculator (and Amps to Watts)
Convert power to current, or current to power, for DC, single-phase AC and three-phase AC — with the power factor where it belongs and the current every common household appliance draws at 230 V.
Watts ⇄ amps
2,300 W on a 230 V single-phase supply at unity power factor (a 2.3 kW geyser)
Power and current
- P
- real power in watts — the power that does work and that the meter bills
- V
- RMS voltage; for three-phase, the line-to-line voltage
- PF
- power factor, cos φ for a sinusoidal supply: 1 for resistive loads
- √3
- 1.732…, because the three phases are 120° apart
Worked example
2,300 W on a 230 V single-phase supply at unity power factor (a 2.3 kW geyser)
I = P ÷ (V × PF) = 2,300 ÷ (230 × 1) = 10 A
Apparent power = 230 × 10 = 2,300 VA — at unity power factor watts and volt-amperes are the same number
The same 2,300 W on a 415 V three-phase supply would be 2,300 ÷ (1.732 × 415 × 1) = 3.20 A per line
A 900 W pump at PF 0.8 draws 900 ÷ (230 × 0.8) = 4.89 A, not the 3.91 A the watts alone suggest
What common appliances draw (resistive loads, unity power factor)
| Appliance | Typical power | At 230 V | At 120 V |
|---|---|---|---|
| LED bulb | 9 W | 0.04 A | 0.07 A |
| Ceiling fan | 75 W | 0.33 A | 0.62 A |
| Television, 43 inch | 100 W | 0.43 A | 0.83 A |
| Refrigerator (running) | 150 W | 0.65 A | 1.25 A |
| Washing machine | 500 W | 2.17 A | 4.17 A |
| Microwave oven | 1,200 W | 5.22 A | 10.00 A |
| Electric iron | 1,000 W | 4.35 A | 8.33 A |
| 1.5 ton air conditioner | 1,500 W | 6.52 A | 12.50 A |
| Water heater (geyser) | 2,000 W | 8.70 A | 16.67 A |
| Electric kettle | 2,200 W | 9.57 A | 18.33 A |
| 1 HP water pump (input) | 900 W | 3.91 A | 7.50 A |
| Induction cooktop | 2,000 W | 8.70 A | 16.67 A |
Converting watts to amps, and back
Watts are power; amps are current. They are connected by the voltage, and on AC by the power factor as well. For direct current the rule is simply I = P ÷ V: a 60 W bulb on a 12 V battery draws 5 A. For single-phase AC the current is I = P ÷ (V × PF), and for a balanced three-phase load the line current is I = P ÷ (√3 × VLL × PF), with VLL the voltage between two lines.
Why the power factor is in there. In an AC circuit with motors, transformers or electronic supplies, current and voltage do not peak at the same instant. The product of RMS volts and RMS amps is the apparent power in volt-amperes; only part of it, VA × PF, does useful work and registers on an energy meter. The cable, the switch and the breaker carry the whole current regardless. A 900 W pump at a power factor of 0.8 draws 4.89 A at 230 V, not the 3.91 A that the watts alone imply — a 25% difference, which is exactly the margin that decides whether a 6 A or a 10 A breaker is right.
Three-phase halves the current twice over. The same 2,300 W drawn from a 415 V three-phase supply is only 3.20 A in each line, against 10 A on single-phase 230 V. That is why workshops, lifts, large air conditioners and any load above roughly 5 kW are wired three-phase: thinner cables, smaller breakers and, for motors, a much better starting characteristic.
Use the current, not the watts. Cable size, breaker rating and voltage drop all follow the current. Convert the load here, then size the cable with the wire size calculator, check the drop with the voltage drop calculator, and pick the protective device with the MCB size calculator. For the relationship between kVA and kW on generators and UPS units, see the kVA to kW calculator; to see what all these loads cost over a month, the electricity consumption calculator.
Frequently asked questions
How many amps is 1000 watts at 230 V?
At unity power factor, 1,000 ÷ 230 = 4.35 A. At a power factor of 0.8 it is 5.43 A. On a 120 V supply the same 1,000 W is 8.33 A.
How do I convert amps to watts?
Multiply: DC watts = A × V; single-phase AC watts = A × V × PF; three-phase watts = √3 × A × VLL × PF. Switch this page to “amps → watts” and it does it for you.
Do I use 230 V or 400 V for a three-phase load?
The line-to-line voltage — 400 V or 415 V — with the √3 in the formula. The 230 V (or 240 V) figure is the phase voltage, line to neutral, which is what single-phase loads in the same installation see.
What power factor should I assume?
1.0 for heating elements, kettles, geysers and filament lamps. About 0.8 for induction motors, pumps and compressors at full load, lower when lightly loaded. Electronic loads vary: equipment with power-factor correction reaches 0.95 or better, cheap drivers can be near 0.5. If the rating plate gives both watts and amps, divide to find the real figure.
Why does my meter show fewer units than the amps suggest?
Domestic meters count real power (kWh), not apparent power. A load with a poor power factor draws current that flows out and back without doing work; you pay for it in cable heating, not in units — though industrial tariffs usually add a penalty for it.
Related calculators
References
- Hughes E, Hiley J, Brown K, Smith I M. Electrical and Electronic Technology, 12th ed. Pearson 2016: three-phase star and delta relationships, the power triangle and power-factor improvement.
- IEC 60038:2009, IEC standard voltages: 230/400 V is the standard low-voltage three-phase system.
- IEC 60364-4-43:2008, Low-voltage electrical installations — Protection against overcurrent, clause 433.1: IB ≤ In ≤ IZ and I2 ≤ 1.45 × IZ.
